System of Equations PostAt a dog park, there were a total of 18 dogs and people combined. There were a total of 50 legs on the dogs and people. How many dogs and people were at the park? Let d = number of dogs at the park; then 4d = total number of legs on the dogs.Let p = number of people at the park; then 2p = total number of legs on the people. Equation 1: The total number of dogs and people at the park is 18: d + p = 18Equation 2: The total number of legs at the park is 50: 4d + 2p = 50 Use substitution to solve the system of equations.Solve Equation 1 for p by subtracting d from each side: p = 18 – dSubstitute 18 – d for p in Equation 2 and then solve for d: 4d + 2(18 – d) = 50 4d + 36 – 2d = 50 distribute on the left side 2d + 36 = 50 combine like terms on the left side 2d = 14 subtract 36 from each side d = 7 divide both sides by 2 If d = 7, then p = 18 – 7 = 11. Check number of legs: 4(7) + 2(11) = 28 + 22 = 50.So there were seven dogs and eleven people at the park.
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