What is the period of the Moon, according to Kepler\’s law?

Project description
Transmission media is the path between the sender and receiver. Transmission media is classified as 1) guided (such as cable and twisted wire) and 2) unguided (which is usually referred to as wireless transmission).

Additionally, the medium is controlled by the error-detection process (error detection and correction) to ensure transmission accuracy.

Parity check is an approach to error detection. In ASCII transmissions, the value bit is selected so that each 7-bit character is attached a 1 for even or odd parity. The receiving end will check, and if a 1 is inverted to 0, an error is detected. In addition, lost frames and damaged frames can occur when data is sent in frame sequence. Error control techniques include positive acknowledgment, retransmission after time-out, negative acknowledgement, and retransmission. Additionally, as an example of satellite transmission media, Keplers law is reviewed for calculating the period a signal reaches earth for satellite transmissions. The orbit section and assignment were extracted from Forouzan (2007, p. 479).

SLP 2 reviews sections 7 and 9 of the Data Communication and Networking e-textbook.


An artificial satellite needs to have an orbitthe path in which it travels around the Earth. The orbit can be equatorial, inclined, or polar. The period of a satellite, the time required for a satellite to make a complete trip around the Earth, is determined by Kepler\’s law, which defines the period as a function of the distance of the satellite from the center of the Earth.

Example 1

What is the period of the Moon, according to Kepler\’s law?

Period:::: C x distance1.5

Here C is a constant approximately equal to 1/100. The period is in seconds and the distance in kilometers.


The Moon is located approximately 384,000 km above the Earth. The radius of the Earth is 6,378 km. Applying the formula, we get:

Example 2

According to Kepler\’s law, what is the period of a satellite that is located at an orbit approximately 35,786 km above the Earth?


Applying the formula, we get:

This means that a satellite located at 35,786 km has a period of 24 h (hours), which is the same as the rotation period of the Earth. A satellite like this is said to be stationary to the Earth. The orbit is called a geosynchronous orbit.

SLP 2 Assignment
Look up the altitude of a Globalstar satellite on the Internet. Use Kepler\’s formula to check the accuracy of a given period and altitude for a Globalstar satellite. Use the following exponent calculator to estimate the period.


Submit the assignment answer in a 2- to 3-page Word document (excluding cover page and references) and explain how you arrived at the period using the Keplers formula.

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