Where Americans smoke marijuana the most.Explain

MKT 439 Assignment 3 Spring 2016– Individual Assignment and Submission
Where Americans smoke marijuana the most
By Christopher Ingraham August 5, 2014
Forget Colorado or Washington — tiny Rhode Island is the marijuana capital of the United States, at least as measured by the percent of state residents who regularly use marijuana.
State-level statistics from the latest National Survey on Drug Use and Health (rather unfortunately acronymed NSDUH) show that just over 1 in 8 Rhode Island residents over age 12 smoke marijuana monthly. This is more than three times the rate in Kansas, where only 4 percent of residents regularly indulge.
Marijuana use in the past month (%), by age group and state
State Total 12+ 12 to 17 18 to 25 25+
Alabama 5.07 5.62 14.34 3.38
Alaska 12.97 10.01 24.72 11.18
Arizona 7.22 8.37 17.20 5.33
Arkansas 5.33 6.01 14.71 3.61
California 9.08 8.83 21.74 6.74
Colorado 10.41 10.47 26.81 7.63
Connecticut 8.44 8.72 23.66 6.01
Delaware 7.49 9.58 20.95 4.95
District of Columbia 10.45 9.35 24.49 7.24
Florida 6.65 7.03 19.02 4.73
Georgia 5.96 7.20 16.65 3.88
Hawaii 7.57 9.69 18.15 5.69
Idaho 5.29 6.21 13.09 3.77
Illinois 7.03 6.94 20.27 4.79
Indiana 6.20 6.25 16.78 4.31
Iowa 6.10 6.65 16.84 4.13
Kansas 4.06 5.47 11.34 2.55
Kentucky 5.63 6.06 17.35 3.65
Louisiana 4.62 5.01 13.00 3.02
Maine 8.38 8.94 22.66 6.29
Maryland 5.81 7.54 17.53 3.66
Massachusetts 9.37 10.58 25.77 6.34
Michigan 8.89 8.89 22.13 6.61
Minnesota 6.30 7.27 17.58 4.33
Mississippi 5.80 6.32 15.86 3.88
Missouri 5.94 7.28 17.41 3.83
Montana 10.45 9.56 26.51 7.94
Nebraska 5.51 6.53 14.83 3.74
Nevada 8.36 8.77 20.01 6.44
New Hampshire 8.37 9.61 26.37 5.41
New Jersey 6.05 6.85 19.26 3.96
New Mexico 9.14 9.82 21.35 6.94
New York 8.24 7.86 21.35 5.98
North Carolina 6.49 7.69 19.28 4.24
North Dakota 5.15 6.02 14.44 3.07
Ohio 7.37 7.53 19.22 5.39
Oklahoma 6.04 6.37 14.14 4.55
Oregon 12.16 9.86 25.81 10.25
Pennsylvania 6.18 6.87 17.54 4.20
Rhode Island 13.00 12.44 30.16 9.74
South Carolina 7.20 7.24 19.24 5.15
South Dakota 5.79 6.44 13.95 4.28
Tennessee 5.41 5.92 14.70 3.81
Texas 5.11 6.32 13.76 3.30
Total U.S. 7.13 7.55 18.89 5.05
Utah 4.41 5.12 9.83 3.04
Vermont 12.86 13.36 33.18 9.34
Virginia 5.54 6.61 17.06 3.44
Washington 10.21 9.45 23.44 8.11
West Virginia 5.27 6.63 17.55 3.29
Wisconsin 6.69 7.78 18.18 4.65
Wyoming 5.68 6.00 13.06 4.36

You are a marketing analyst for a marketing research firm and have been asked to perform an analysis of the data contained in this article. Your firm has been contracted by the state of New Jersey as it considers some form of legalization of marijuana to be placed on an upcoming ballot measure in 2017.
It is important to note that the requested analysis is based upon sample data, not population data.
To answer the questions and complete the analysis below, you can use a pen and paper, a calculator, import to Microsoft Excel, JMP Software or any other software you’d like. Make sure you show your work and/or provide an explanation so I can understand how you arrived at your answers.
Using the data in the “Total 12+” column, create a graphical Frequency Distribution of this data for each state.
In tabular format, using the data in the “Total 12+” column, develop a Percentage Distribution of the number of states for values:
<5.0
5.1 – 6.0
6.1 – 7.0
7.1 – 8.0
8.1 – 9.0
9.1 – 10.0
>10.0
Using the data in the “18 to 25” column, what Proportion of states have usage at or above 20.00%? Express this as a percentage.
Which age group 12 – 17, 18 – 25 or 25+ has the highest Mean of individuals using marijuana? What is that mean?
Using the data in the “18 to 25” column, what is the Median of the data?
What is the Range for each of the data in each of the four columns above? Which age range has the lowest dispersion and which age range has the highest dispersion? What are the values for each (i.e. the value of the dispersion between the smallest and largest value in the lowest dispersion and highest dispersion).
7. Using the data in the “18 to 25” column, calculate the Standard Deviation. Show the Standard Deviation Equation. Hint: There are 51 entries as it includes the District of Columbia. Count each state plus the District of Columbia as “one” unit of the sample to determine sample size.
8. Calculate the Confidence Interval for the data in the “18 to 25” column. Refer to page 379 in the 6th Edition of the textbook. Hint: Use the formula at the bottom of page 379:
a. µ = X(bar) +/- (Z*(S/Sq root n))

b. Let’s assume we want to be 95% confident with the estimates from the sampling from each of the 50 states plus the District of Columbia. Therefore, the Z value to ensure that one-half of the distribution from each side of the mean is included is 1.96.

c. The result of this calculation tells us that the µ (the true mean percentage for the population of 18 to 25 year olds) will be between x% and y%, 95% of the time.

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